Volume of a bead with square hole- Program approach?
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11-08-2023, 02:11 AM
(This post was last modified: 11-08-2023 02:14 AM by DM48.)
Post: #32
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RE: Volume of a bead with square hole- Program approach?
Link to derivation of formula.
\( \int_{0}^{a} \int_{0}^{\sqrt{d^2-y^2-b^2}}\sqrt{d^2-y^2-x^2}-b\text{ }dx\text{ }dy\text{ }+\int_{a}^{d}\int_{0}^{\sqrt{d^2-y^2}}\sqrt{d^2-y^2-x^2}\text{ }dx\text{ }dy \) In[842]:= Clear[a, b, q, r, x] d = 12 a = 2 b = 2 q = NIntegrate[ Integrate[ Sqrt[d^2 - y^2 - x^2] - b, {x, 0, Sqrt[d^2 - y^2 - b^2]}], {y, 0, a}] r = NIntegrate[ Integrate[Sqrt[d^2 - y^2 - x^2], {x, 0, Sqrt[d^2 - y^2]}], {y, a, d}] q + r Out[848]= 857.2260543948448 a=4 b=2 d=12 Out[849]=811.0424359298954 HP48GX, HP42s and DM42. |
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