How to easily crash an HP Prime - Printable Version +- HP Forums (https://www.hpmuseum.org/forum) +-- Forum: HP Calculators (and very old HP Computers) (/forum-3.html) +--- Forum: HP Prime (/forum-5.html) +--- Thread: How to easily crash an HP Prime (/thread-10282.html) |
How to easily crash an HP Prime - Ummon - 03-06-2018 09:09 AM I'm using the latest version : 2018.02.12 1.4.1.13441
It also crashes with the virtual calculator on Windows. RE: How to easily crash an HP Prime - Marcel - 03-07-2018 02:04 PM Hi! Same for me... my calculator reboot. Marcel RE: How to easily crash an HP Prime - Arno K - 03-07-2018 03:11 PM Funny enough that you tried to integrate a trigonometric function in degrees. Arno RE: How to easily crash an HP Prime - Marcel - 03-07-2018 05:34 PM Hi, Here, the angular mode is not the problem.. The prime don't have to reboot on this simple calculation. Marcel RE: How to easily crash an HP Prime - John Colvin - 03-07-2018 07:23 PM Mine crashes also. Interestingly, the same integral dosen't crash my 49G+ in degree mode, but it does give an incorrect answer - 4.66682... But the fact remains that the Prime should not crash simply because the degree mode is used instead of radian mode. Definitely a bug. RE: How to easily crash an HP Prime - Carsen - 03-08-2018 04:48 AM John Colvin. My HP 50g got the right answer of 4.66829167156. I believe the 49G+ should get the right answer as well. Did you accidentally put in the lower and upper bound in the wrong order? RE: How to easily crash an HP Prime - Joe Horn - 03-08-2018 05:04 AM (03-08-2018 04:48 AM)Carsen Wrote: My HP 50g got the right answer of 4.66829167156. Your answer is what the 50g gets in FIX 4 mode, leaving a pretty big value stored in IERR. STD mode takes a few seconds longer but returns 4.66829104623 with a much smaller IERR. RE: How to easily crash an HP Prime - parisse - 03-08-2018 06:37 AM This bug is already fixed in source code. Until it is available in a new firmware, you can run int(sin(x^2),x,0,10.0) RE: How to easily crash an HP Prime - Carsen - 03-08-2018 06:45 AM (03-08-2018 05:04 AM)Joe Horn Wrote:(03-08-2018 04:48 AM)Carsen Wrote: My HP 50g got the right answer of 4.66829167156. Huh. That's neat. I did not know about Integration Error (IERR) variable. I also didn't know (or forgot) that the number format changes the precision of the answer. Like the 15C. Learn something new everyday. Thanks Joe Horn. RE: How to easily crash an HP Prime - DA74254 - 03-08-2018 02:41 PM I tried in on my SM42. It went into an indefinite loop. Even with accuracy of 0.1 RE: How to easily crash an HP Prime - jebem - 03-08-2018 03:04 PM (03-08-2018 02:41 PM)DA74254 Wrote: I tried in on my SM42. It went into an indefinite loop. Even with accuracy of 0.1 "SM42" or "DM42"? Anyway, it is always better to experience a machine reset than an infinite loop, so in this regard the HP Prime wins hands down RE: How to easily crash an HP Prime - DA74254 - 03-08-2018 03:20 PM (03-08-2018 03:04 PM)jebem Wrote:(03-08-2018 02:41 PM)DA74254 Wrote: I tried in on my SM42. It went into an indefinite loop. Even with accuracy of 0.1 SM DM42 Anyway, I was a bit quick as I set up sin (x^3) which went on and on. With the correct integration it spent abt 4 sec. to get 0.5836... in RAD and almost instantly 4.6682... in DEG mode. (And 4.3825... in GRAD mode) RE: How to easily crash an HP Prime - John Colvin - 03-08-2018 08:25 PM (03-08-2018 04:48 AM)Carsen Wrote: John Colvin. My HP 50g got the right answer of 4.66829167156. I believe the 49G+ should get the right answer as well. Did you accidentally put in the lower and upper bound in the wrong order? Am I missing something here? How is 4.6668.... the correct answer? If I convert 10 deg. to pi/18 red. in the upper boundary, I get a result of 0.001772.... on my 50G as well. A graph of sin(x^2) clearly indicates that in this interval, the area under the curve is quite small. RE: How to easily crash an HP Prime - Joe Horn - 03-08-2018 08:47 PM (03-08-2018 08:25 PM)John Colvin Wrote:(03-08-2018 04:48 AM)Carsen Wrote: John Colvin. My HP 50g got the right answer of 4.66829167156. I believe the 49G+ should get the right answer as well. Did you accidentally put in the lower and upper bound in the wrong order? Yes, 10_deg = pi/18_rad, but sin((10_deg)^2) is not the same as sin((pi/18_rad)^2). Plot the sin(x^2) from 0_deg to 10_deg and you'll see it. The integral from 9 to 10 alone is almost 1. RE: How to easily crash an HP Prime - John Colvin - 03-08-2018 09:09 PM (03-08-2018 08:47 PM)Joe Horn Wrote:(03-08-2018 08:25 PM)John Colvin Wrote: Am I missing something here? How is 4.6668.... the correct answer? If I convert That''s what I missed, Joe. Thanks. |