(35S) Formula for Fibonacci Numbers - Printable Version +- HP Forums (https://www.hpmuseum.org/forum) +-- Forum: HP Software Libraries (/forum-10.html) +--- Forum: General Software Library (/forum-13.html) +--- Thread: (35S) Formula for Fibonacci Numbers (/thread-1450.html) |
(35S) Formula for Fibonacci Numbers - Gerald H - 05-29-2014 05:24 AM The formula finds the exact Fibonacci number for positive integer N on stack level X for N from 0 to 59, for higher values the result is approximate: IP(((1+√5)÷2)^REGX÷√5+.4)-IDIV(REGX,56)-2*IDIV(REGX,58)-2*IDIV(REGX,59) Improvements or alternative approaches welcome. NB In case REGX is unfamiliar, access to REGX when entering a programme is via "EQN" key, setting algebraic mode, "R↓" key, giving access to registers x, y, z & t, & then choosing the desired register, ie REGX is the content of stack level X. |