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(Casio fx-CG50/9750GIII): System of Two Differential Equations - Eddie W. Shore - 08-02-2020 02:38 PM
Blog link: http://edspi31415.blogspot.com/2020/08/casio-fx-9750giii-and-fx-cg50-system-of.html
Solving systems of differential equations would be a nice addition to the HP Prime. Here it is for the Casio fx-9750GIII/fx-CG 50:
The program TWORK4 uses the Runge Kutta 4th Order method to solve the following system of differential equations:
dx/dt = f(t, x, y)
dy/dt = g(t, x, y)
with initial conditions x0 = x(t0) and y0 = y(t0)
The next step is calculated with step h from:
x1 ≈ x0 + (k1 + 2 * k2 + 2 * k3 + k4) / 6
y1 ≈ y0 + (l1 + 2 * l2 + 2 * l3 + l4) / 6
k1 = h * f(t0, x0, y0)
l1 = h * g(t0, x0, y0)
k2 = h * f(t0 + h / 2, x0 + k1 / 2, y0 + l1 / 2)
l2 = h * g(t0 + h / 2, x0 + k1 / 2, y0 + l1 / 2)
k3 = h * f(t0 + h / 2, x0 + k2 / 2, y0 + l2 / 2)
l3 = h * g(t0 + h / 2, x0 + k2 / 2, y0 + l2 / 2)
k4 = h * f(t0 + h, x0 + k3, y0 + l3)
l4 = h * g(t0 + h, x0 + k3, y0 + l3)
For the next step set t0 = t0 + h, x0 = x1, and y0 = y1.
Inputs:
DX/DT: Enter dx/dt as a function of T, X, and Y. T is the independent variable.
DY/DT: Enter dy/dt as a function of T, X, and Y. T is the independent variable.
T0, X0, Y0: Enter the initial conditions
STEP: Enter the step size
ITERATIONS: Enter the number of iterations desired. This allows you to calculate a far point in one leap. Example, if your initial condition is to = 0 and you want to find the point when t = 1 using the step size of 0.1, enter 0.1 for STEP and 10 for ITERATIONS.
Casio fx-9750GIII and fx-CG 50 Program: TWORK4
Notes:
* Although the code for the two calculators are the same, the programs will need to be programmed on each calculator separately.
* The slash character (/) is accessed from the CHAR submenu. The submenu shows up at the top-level menu which would read:
TOP/BOTTOM/SEARCH/MENU/A ←→ a/CHAR
* fn1 and fn2 are stored as function memories.
Code:
"2020-06-18 EWS"
Rad
"DX/DT="? → fn1
"DY/DT="? → fn2
"T0"? → U
"X0"? → A
"Y0"? → B
"STEP?" → H
4 → Dim List 25
4 → Dim List 26
Lbl 0
"ITERATIONS"? → N
For 1 → I To N
A → X: B → Y: U → T
H * fn1 → List 25[1]
H * fn2 → List 26[1]
A + List 25[1] ÷ 2 → X
B + List 26[1] ÷ 2 → Y
U + H ÷ 2 → T
H * fn1 → List 25[2]
H * fn2 → List 26[2]
A + List 25[2] ÷ 2 → X
B + List 26[2] ÷ 2 → Y
H * fn1 → List 25[3]
H * fn2 → List 26[3]
A + List 25[3] → X
B + List 26[3] → Y
U + H → T
H * fn1 → List 25[4]
H * fn2 → List 26[4]
A + (List 25[2] + List 25[3] + Sum List 25) ÷ 6 → A
B + (List 26[2] + List 26[3] + Sum List 26) ÷ 6 → B
U + H → U
Next
ClrText
"(T, X, Y)"
{U, A, B} ◢
Menu "NEXT?", "YES", 0, "NO", 1
Lbl 1
"DONE"Example
dx/dt = x sin y
dy/dt = y^2/500 + y/3 - y
Initial conditions: x(0) = 0.1, y(0) = 0.1, h = 0.1
T0 = 0
STEP = 0.1
ITERATIONS: 10
Results: (T, X, Y): (1, 0.1075645239, 0.05134921355)
ITERATIONS: 10
Results: (T, X, Y): (2, 0.1116714419, 0.02636554462)
Source:
John W. Harris and Horst Stocker. Handbook of Mathematics and Computational Science. Springer: New York. 2006. ISBN 978-0-387-94746-4
Stack Exchange. "Help with using the Runge-Kutta 4th order method on a system of 2 first order ODE'S" Asked March 2014. Last updated February 2019. https://math.stackexchange.com/questions/721076/help-with-using-the-runge-kutta-4th-order-method-on-a-system-of-2-first-order-od Retrieved June 17, 2020
RE: (Casio fx-CG50/9750GIII): System of Two Differential Equations - Ioncubekh - 10-28-2022 09:33 AM
@ https://www.hpmuseum.org/forum/thread-19012.html
One can use this above. Its working & I have checked.