How to use graphic.draw_filled_polygon?

How to use graphic.draw_filled_polygon? - Printable Version

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How to use graphic.draw_filled_polygon? - jfelten - 08-23-2021 08:09 PM

Whenever I try to run a command like

Code:

>from graphic import *

>draw_filled_polygon([[0,0,0], [0,240,0], [160, 120, 0]], 0)

it just draws nothing and prints "False" to the console. Any other form on syntax either gives me an error or crashes the calculator. I could not find any documentation for this module, so I have no idea how the command works.

RE: How to use graphic.draw_filled_polygon? - pol95 - 08-26-2021 02:23 AM

(08-23-2021 08:09 PM)jfelten Wrote: Whenever I try to run a command like

Code:

>from graphic import * >draw_filled_polygon([[0,0,0], [0,240,0], [160, 120, 0]], 0)
it just draws nothing and prints "False" to the console. Any other form on syntax either gives me an error or crashes the calculator. I could not find any documentation for this module, so I have no idea how the command works.

Lo leí en TI planet y funciona.

MODERATOR NOTE: English please in the forums. Google translation: "I read it on TI planet and it works."

Code:

>from graphic import *

>draw_filled_polygon([[0,0], [0,240], [160, 120]], magenta)

RE: How to use graphic.draw_filled_polygon? - jfelten - 08-26-2021 02:50 AM

So I did manage to find the official documentation for this library after digging through TI Planet forums a bit, and I found out the the correct syntax was

Code:

draw_filled_polygon([[x1, y1], [x2, y2], ..., [xn, yn]], couleur)

although whenever I try that, it crashes the calculator. Is this a bug with the python interpreter or is it just picky about which values or how many values I use?

RE: How to use graphic.draw_filled_polygon? - albud44 - 08-31-2021 08:01 PM

(08-26-2021 02:50 AM)jfelten Wrote: So I did manage to find the official documentation for this library after digging through TI Planet forums a bit, and I found out the the correct syntax was

Code:

draw_filled_polygon([[x1, y1], [x2, y2], ..., [xn, yn]], couleur)
although whenever I try that, it crashes the calculator. Is this a bug with the python interpreter or is it just picky about which values or how many values I use?

Hello,

Sorry, in french, m'y english is little.

Et avec couleur=(r,g,b) ?

Ça donne quoi ?

RE: How to use graphic.draw_filled_polygon? - jfelten - 09-04-2021 07:43 PM

(08-31-2021 08:01 PM)albud44 Wrote:
(08-26-2021 02:50 AM)jfelten Wrote: So I did manage to find the official documentation for this library after digging through TI Planet forums a bit, and I found out the the correct syntax was

Code:

draw_filled_polygon([[x1, y1], [x2, y2], ..., [xn, yn]], couleur)
although whenever I try that, it crashes the calculator. Is this a bug with the python interpreter or is it just picky about which values or how many values I use?

Hello,

Sorry, in french, m'y english is little.

Et avec couleur=(r,g,b) ?

Ça donne quoi ?

Here is what I got:

Code:

>from graphic import *

>draw_filled_polygon([[0,0],[0,240],[160,120]],(0,0,0))

Traceback (most recent call last):

  File "<stdin>", line 1, in <module>

TypeError: can't convert tuple to int

RE: How to use graphic.draw_filled_polygon? - Guenter Schink - 09-04-2021 08:53 PM

(09-04-2021 07:43 PM)jfelten Wrote: Here is what I got:

Code:

>from graphic import * >draw_filled_polygon([[0,0],[0,240],[160,120]],(0,0,0)) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: can't convert tuple to int

That's weird! The following code works on the virtual Prime and on the G1, but crashes the G2

Code:

>from graphic import *

>draw_filled_polygon([[0,0],[0,240],[160,120]],0xff)

gives a nice blue triangle.

"draw_polygon" however works as expected. When I was working on my "Mandelbrot Explorer" I tried a lot with the "graphic" module but gave up. It was completely useless.

Günter

Where did you find the documentation?

RE: How to use graphic.draw_filled_polygon? - jfelten - 09-04-2021 11:10 PM

https://tiplanet.org/forum/viewtopic.php?f=55&t=24828&sid=85037c13ec9d16ab7f46d898dfc35618

RE: How to use graphic.draw_filled_polygon? - Guenter Schink - 11-28-2021 10:25 PM

with the last update 2021-11-25 it's now working on the G2 too.
<draw_filled_polygon()> obviously needs two parameters. one list of the co-ordinates an one color.

E.g:
from graphic import *
draw_filled_polygon(((0,0),(160,120),(0,240)),blue)

instead of making it all <tuple> seems we can mix <list> and <tuple>. This works also:
draw_filled_polygon([(0,0),(160,120),(0,240)],blue) or even a mix(ugly):
draw_filled_polygon([[0,0],(160,120),(0,240)],blue)

Günter

RE: How to use graphic.draw_filled_polygon? - StephenG1CMZ - 11-29-2021 12:42 AM

(09-04-2021 07:43 PM)jfelten Wrote:
(08-31-2021 08:01 PM)albud44 Wrote: Hello,

Sorry, in french, m'y english is little.

Et avec couleur=(r,g,b) ?

Ça donne quoi ?

Here is what I got:

Code:

>from graphic import * >draw_filled_polygon([[0,0],[0,240],[160,120]],(0,0,0)) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: can't convert tuple to int

Just a thought, if it can't convert tuple to int, is it expecting #nnn for colour instead of (255 255 255)?

RE: How to use graphic.draw_filled_polygon? - Guenter Schink - 11-29-2021 10:04 AM

(11-29-2021 12:42 AM)StephenG1CMZ Wrote:
(09-04-2021 07:43 PM)jfelten Wrote: Here is what I got:

Code:

>from graphic import * >draw_filled_polygon([[0,0],[0,240],[160,120]],(0,0,0)) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: can't convert tuple to int

Just a thought, if it can't convert tuple to int, is it expecting #nnn for colour instead of (255 255 255)?

Yes, an integer is required, be it decimal or hex. A little "lambda" may be of help to create it rather than calculate it by hand. E.g:

Code:

RGB=lambda red, green, blue: (((red*256)+green)*256)+blue

draw_filled_polygon([(0,0),(160,120),(0,240)],RGB(120,120,120))

gets you a grey triangle

Günter

RE: How to use graphic.draw_filled_polygon? - toml_12953 - 11-29-2021 02:22 PM

(11-29-2021 10:04 AM)Guenter Schink Wrote:
(11-29-2021 12:42 AM)StephenG1CMZ Wrote: Just a thought, if it can't convert tuple to int, is it expecting #nnn for colour instead of (255 255 255)?

Yes, an integer is required, be it decimal or hex. A little "lambda" may be of help to create it rather than calculate it by hand. E.g:

Code:

RGB=lambda red, green, blue: (((red*256)+green)*256)+blue draw_filled_polygon([(0,0),(160,120),(0,240)],RGB(120,120,120))

gets you a grey triangle

Günter

I'm a Python beginner. Can you tell me why use lambda over the following? What's the advantage?

Code:

def RGB(red,green,blue):

  return (((red*256)+green)*256)+blue

RE: How to use graphic.draw_filled_polygon? - Guenter Schink - 11-29-2021 08:40 PM

(11-29-2021 02:22 PM)toml_12953 Wrote:
(11-29-2021 10:04 AM)Guenter Schink Wrote: Yes, an integer is required, be it decimal or hex. A little "lambda" may be of help to create it rather than calculate it by hand. E.g:

Code:

RGB=lambda red, green, blue: (((red*256)+green)*256)+blue draw_filled_polygon([(0,0),(160,120),(0,240)],RGB(120,120,120))

gets you a grey triangle

Günter

I'm a Python beginner. Can you tell me why use lambda over the following? What's the advantage?

Code:

def RGB(red,green,blue): return (((red*256)+green)*256)+blue

I'm a Python beginner too Smile

Both are equivalent. Once something can be done in a one liner I'm tempted to do this.
In principle, as a beginner, I try to use some language specifics where I see them fit.
Here is some discussion on this subject. In short: you don't need it, but it may serve you well once you're accustomed to it.

Usually you would use <lambda> as an anonymous function directly:

Code:

draw_filled_polygon([(0,0),(160,120),(0,240)],(lambda red, green, blue: (((red*256) +green) *256) +blue)(120,120,100))

the arguments of the lambda function can of course be variables

Günter