What does G_0 mean when using desolve? - Printable Version +- HP Forums (https://www.hpmuseum.org/forum) +-- Forum: HP Calculators (and very old HP Computers) (/forum-3.html) +--- Forum: HP Prime (/forum-5.html) +--- Thread: What does G_0 mean when using desolve? (/thread-17489.html) What does G_0 mean when using desolve? - pvp100288840 - 09-20-2021 03:33 AM Hi everyone, I just started to learn calculus and I was using HP Prime to solve some differential equation with desolve. For example I entered following command: Code: ` desolve(d(y,x))=(y^2-4) )` And I got following result: Code: `[(-2*G_0*e^(4*x)-2)/(G_0*e^(4*x)-1)]` So what does G_0 mean? It doesn't look like 'y' or something.... RE: What does G_0 mean when using desolve? - lrdheat - 09-20-2021 04:35 AM G_# refers to a constant. If you specified boundary conditions, you would get the result for those specific conditions as opposed to a constant covering a general solution. RE: What does G_0 mean when using desolve? - Albert Chan - 09-20-2021 01:33 PM Note that integration also generate constant of integration. But, if we use integrated result, F(x), to evaluate F(b) - F(a), the constant cancelled. Thus, HP Prime CAS (and many other CAS) did not return the constant. XCAS> ∫(x,x) ﻿ ﻿ ﻿ ﻿ ﻿ ﻿ → x^2/2 Although constant is not reported, keep in mind it is there ...