Is it possible to do other kinds of systems of linear equations? - Printable Version +- HP Forums (https://www.hpmuseum.org/forum) +-- Forum: HP Calculators (and very old HP Computers) (/forum-3.html) +--- Forum: HP Prime (/forum-5.html) +--- Thread: Is it possible to do other kinds of systems of linear equations? (/thread-20253.html) |
Is it possible to do other kinds of systems of linear equations? - batx27 - 08-01-2023 05:38 PM The linear solver only takes x+y=z x+y=z Is it possible to do an equation like 10x-4y=8 8y=kx-30 RE: Is it possible to do other kinds of systems of linear equations? - MarkB - 08-02-2023 07:38 AM (08-01-2023 05:38 PM)batx27 Wrote: Is it possible to do an equation like As the User Guide says (Section 16 on page 312 in my copy) equations must be in the form: ax + by = k (for the 2x2 solver) ax + by + cz = k (for the 3x3 solver) Simply rearrange any equations to fit the appropriate form and then enter the coefficients into the boxes. 10x - 4y = 8 is already [10]x + [-4]y = [8] 8y = kx - 30 becomes [k]x + [-8]y = [30] (presumably you know "k") RE: Is it possible to do other kinds of systems of linear equations? - batx27 - 08-02-2023 10:06 PM Hey Mark. I actually don't know the value for K, so I wondering if there was a shortcut or program to find K, but I guess I will keep looking. Thanks tho RE: Is it possible to do other kinds of systems of linear equations? - Aries - 08-03-2023 05:00 AM Assuming the parameter k>0, you should see something like: x=14/(k-20) and y=(75-2k)/(k-20) Best, Aries ;-) RE: Is it possible to do other kinds of systems of linear equations? - nickapos - 08-03-2023 05:51 AM (08-02-2023 10:06 PM)batx27 Wrote: Hey Mark. I actually don't know the value for K, so I wondering if there was a shortcut or program to find K, but I guess I will keep looking. Thanks tho There is no way to solve a 2 equation system with 3 unknowns. One of them (k in this case) will have to remain unknown and you will have to express the x and y in terms of k. Your system will have infinite solutions, unless you have a restriction for k. For each separate value of k you will have a different solution. |