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+--- Thread: Laplace transform of pde ∂u/∂t = 0.01 * ∂²u/∂x² using the Prime (/thread-20525.html)
Laplace transform of pde ∂u/∂t = 0.01 * ∂²u/∂x² using the Prime - Anthony The Koala - 09-20-2023 11:28 AM
Generally if we have a function that is "common" we can find L{f(x}} and get the corresponding transform.
Example L{5} = 5/s.
You can find the table in any 2nd year book.
I would like to know how to get a Laplace transform on the Prime.
For example:
pde
∂u/∂t = 0.01 * ∂²u/∂x²
Boundary conditions:
u(0, t) = 0
u(1, t) = 200
I tried the laplace L{∂u/∂t}
expecting to get
L{∂u/∂t} = sU(x,s) - u(x,0)
BUT IN THE PRIME
laplace(∂u/∂t)
I get "X Syntax Error"
Can you get laplace transforms of derivatives?
Thank you
Anthony, Sydney