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Math problem where graphing calculator may slow you down - part II. - CR Haeger - 09-12-2014 12:43 PM Hello - here is a problem that should be fairly easily solvable by hand and with a trig table: Assume f(x) = max(sin(x), cos(x)) using radians. If the area under the curve f(x) = 4.0 and the lower limit of x = 0.0, what is the upper limit of integration? What do your machines and/or brains come up with? Note - I got this to work on the HP Prime using the AREA() function in Function APP, but had problems using solve() or fsolve() properly. Num-Solv on a TI36x had to think about this a looong time. RE: Math problem where graphing calculator may slow you down - part II. - Marcus von Cube - 09-12-2014 04:33 PM (09-12-2014 12:43 PM)CR Haeger Wrote: If the area under the curve f(x) = 4.0Is the area positive if the function is negative? Or are we just talking about the definite integral? EDIT: If the area is always positive, the answer 2π. I split the interval at π/4, π, π+π/4, π+π/2, 2π. All the square roots cancel each other. RE: Math problem where graphing calculator may slow you down - part II. - CR Haeger - 09-12-2014 05:22 PM (09-12-2014 04:33 PM)Marcus von Cube Wrote:(09-12-2014 12:43 PM)CR Haeger Wrote: If the area under the curve f(x) = 4.0Is the area positive if the function is negative? Or are we just talking about the definite integral? Hi Marcus, I should have stated that its a definite integral where area is negative when f(x) is negative. Your solution and abs(f(x)) are interesting too - thanks! RE: Math problem where graphing calculator may slow you down - part II. - Thomas Klemm - 09-13-2014 04:54 AM My solution by hand: \(2\pi+\arccos(3\sqrt{2}-4)\) This is about: 7.6089 I used the HP-15C with this program to calculate the function: Code: LBL A Cheers Thomas RE: Math problem where graphing calculator may slow you down - part II. - Bunuel66 - 09-13-2014 09:12 PM By hand and a bit of brain.... f(x) is periodic with a 2pi period. from 0 to pi/4 f(x)=cos(x) from pi/4 to 5pi/4 f(x)=sin(x) from 5pi/4 to 2pi f(x)=cos(x) Integrating is straightforward and gives 4/sqrt(2) over 0 to 2pi going up to 9pi/4 gives 5/sqrt(2). Then the value searched for is between 9pi/4 and 9pi/4+pi, in other words on the second interval of the definition of f(x). This equivalent to search for X with: sum from pi/4 to X of sin(x) dx=4-5/sqrt(2). Integrating analytically and solving lead to: X=acos(6/sqrt(2)-4) The solution is then 9pi/4+X-pi/4~7.6089 Nothing more necessary than any standard scientific calculator... BTW, I'm cheating slightly, I checked the value of the integral with my own python software ;-) which uses a HP like algorithm.... RE: Math problem where graphing calculator may slow you down - part II. - Thomas Klemm - 09-14-2014 02:18 PM (09-13-2014 09:12 PM)Bunuel66 Wrote: Integrating is straightforward and gives 4/sqrt(2) over 0 to 2pi We should make sure that the integral is always < 4. Thus we calculate it up to the first zero of the function \(f(x)\) which occurs at \(x=\pi\): \[ \int_{0}^{\pi}\max(\sin(x),\cos(x))dx=1+\sqrt{2}\approx 2.41421 \] Cheers Thomas RE: Math problem where graphing calculator may slow you down - part II. - Bunuel66 - 09-14-2014 07:22 PM Actually I made the check for the first maximum, I wanted just not to be too long with the explanations, just giving the general idea. Regards RE: Math problem where graphing calculator may slow you down - part II. - Gilles - 11-14-2014 10:01 PM I used the numeric solver of the 50G in FIX 4 FIX 6 takes more time and returns X: 7.608894 This help to get the exact answer with the 50G CAS : 'X=2*PI+ACOS(3*SQRT(2)-4)' RE: Math problem where graphing calculator may slow you down - part II. - CR Haeger - 11-16-2014 04:06 PM Thanks Giles, Has anyone tried solving this using the HP Prime CAS, Home or Function APP? It seems to me there are only a couple of ways to find a numeric solution. I have not found any exact solution using the device either. Screenshot with CAS settings Exact, Complex and Use i unchecked. [attachment=1213] Graphically, it worked out pretty well, once I figured out AREA() syntax. Note that using integral from template did not work for me. [attachment=1214] [attachment=1215] RE: Math problem where graphing calculator may slow you down - part II. - Gilles - 11-16-2014 08:40 PM Hi CR Haeger, I tried with the Prime both in CAS and with the SOLVE APPS without success. I agree with you about the plotter of the Prime : just fabulous ! I like very much to zoom instantly with 2 fingers RE: Math problem where graphing calculator may slow you down - part II. - lrdheat - 11-28-2014 06:17 PM I'm amazed at the TI 36 Pro. It took 30+ minutes (in numsolve), but it came up with the result! RE: Math problem where graphing calculator may slow you down - part II. - lrdheat - 11-29-2014 12:49 AM I sped things up to under 15 minutes by doing a couple of experimental integrations to get an idea of where the integral would be ~4, then a quick table to zoom in on an appropriate guess, and then enter a good guess into numsolve. RE: Math problem where graphing calculator may slow you down - part II. - lrdheat - 11-29-2014 03:31 AM ...which leads me to...how to accomplish this on the WP-34S? How do I solve for an integral ? RE: Math problem where graphing calculator may slow you down - part II. - Thomas Klemm - 11-29-2014 09:30 AM (11-29-2014 03:31 AM)lrdheat Wrote: how to accomplish this on the WP-34S? It's similar to what you do using the HP-15C: Code: LBL'FX' Code: LBL'IGR' RAD FIX 4 7.6 7.61 SLV'IGR' 7.6089 Cheers Thomas RE: Math problem where graphing calculator may slow you down - part II. - CR Haeger - 11-29-2014 01:52 PM (11-29-2014 12:49 AM)lrdheat Wrote: I sped things up to under 15 minutes by doing a couple of experimental integrations to get an idea of where the integral would be ~4, then a quick table to zoom in on an appropriate guess, and then enter a good guess into numsolve. Try turning off pretty print mode and setting the integrals resolution to say 0.1. May speed things up. I agree - the TI36x is pretty straightforward and capable for these type if solver problems. RE: Math problem where graphing calculator may slow you down - part II. - lrdheat - 11-30-2014 01:33 AM Thanks Thomas, It works...couldn't remember how to have an integral in solve. Rather slow on this sort of problem! RE: Math problem where graphing calculator may slow you down - part II. - Thomas Klemm - 11-30-2014 12:16 PM (11-30-2014 01:33 AM)lrdheat Wrote: Rather slow on this sort of problem! For this specific problem the derivative is trivial: \[ \begin{align} F(x)&=\int_{0}^{x}f(t)dt-4 \\ F'(x)&=f(x) \\ \end{align} \] Thus we can use Newton's method: \[ \begin{align} x'&=x-\frac{F(x)}{F'(x)} \\ &=x-\frac{\int_{0}^{x}f(t)dt-4}{f(x)} \\ &=x+\frac{\int_{x}^{0}f(t)dt+4}{f(x)} \\ \end{align} \] Instead of starting the integration from \(0\) over and over again we can reuse the result of \(F(x)\) from the previous loop: \[ F(x')=F(x)+\int_{x}^{x'}f(t)dt \] This value is saved in register 01. Code: LBL'FX' Code: LBL'NWT' This will speed up the calculation. Cheers Thomas RE: Math problem where graphing calculator may slow you down - part II. - lrdheat - 11-30-2014 07:04 PM Excellent, clear, concise as usual. |