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+--- Thread: Could anybody help me with solving this equation? (/thread-22850.html)
Could anybody help me with solving this equation? - Assassinatemax - 12-13-2024 09:18 PM
I got a equation here and I don't know why I cannot solve for it, I attached the formula I input in the picture.
I really appreiate any help.
RE: Could anybody help me with solving this equation? - Albert Chan - 12-14-2024 03:38 PM
Try replacing approximate number 0.01 as 1/100
Cas> m1 := [[-p1*t1+1, t1], [-p1^2*t1, p1*t1+1]]
Cas> solve([-m1(1,1)/-m1(2,1)=50, -m1(2,1)=1/100], [p1,t1])
{[1/150, 225]}
Or, do this symbolically, then replace with approx. numbers
Cas> solve([-m1(1,1)/-m1(2,1)=a, -m1(2,1)=b], [p1,t1]) (a=50, b=0.01)
{[6.66666666667e−3, 225.]}
RE: Could anybody help me with solving this equation? - Thomas Klemm - 12-15-2024 06:09 AM
Solve it manually:
\(
\begin{align}
\frac{-(-pt+1)}{-(-p^2t)}&=50 \\
-(-p^2t)&=\frac{1}{100} \\
\end{align}
\)
Plug 2nd equation into 1st:
\(
\begin{align}
pt-1&=\frac{50}{100} \\
p^2t&=\frac{1}{100} \\
\end{align}
\)
Add 1 on both sides of 1st equation:
\(
\begin{align}
pt&=\frac{150}{100} \\
p^2t&=\frac{1}{100} \\
\end{align}
\)
Plug 1st equation into 2nd:
\(
\begin{align}
pt&=\frac{150}{100} \\
p&=\frac{1}{150} \\
\end{align}
\)
Plug 2nd equation into 1st:
\(
\begin{align}
t&=\frac{150^2}{100}=15^2=225 \\
p&=\frac{1}{150} \\
\end{align}
\)