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+--- Thread: trigcos() function (/thread-2388.html)
trigcos() function - DrD - 11-04-2014 12:40 PM
s:=√((sin(t))²+(-cos(t)+1)²)
k:=expand(s) ---> √(-2*cos(t)+(cos(t))²+1+(sin(t))²)
trigcos(√(-2*cos(t)+(cos(t))²+1+(sin(t))²)) ---> √(-2.*cos(t)+2.)
trigcos(k) ---> 2.*ABS(sin(0.5*t))
With both trigcos() cases the same, why the additional simplification on trigcos(k)?
How can I get the trigcos(k) result: √(-2.*cos(t)+2.)?
Thanks,
-Dale-
RE: trigcos() function - parisse - 11-04-2014 02:22 PM
Maybe because you are not in exact mode.