root of a quadratic equation - Printable Version +- HP Forums (https://www.hpmuseum.org/forum) +-- Forum: HP Calculators (and very old HP Computers) (/forum-3.html) +--- Forum: General Forum (/forum-4.html) +--- Thread: root of a quadratic equation (/thread-4554.html) |
root of a quadratic equation - tigger - 08-22-2015 09:41 AM These two equations help to solve a root of a quadratic equation: << 2 ->LIST SWAP / EVAL SWAP -2 / DUP SQ ROT - v/ DUP2 + ROT ROT - >> << 3 PICK / SWAP ROT -2 * / DUP SQ ROT - SQRT DUP2 * ROT ROT - >> [quote='tigger' pid='40913' dateline='1440236517'] << 2 ->LIST SWAP / EVAL SWAP -2 / DUP SQ ROT - v/ DUP2 + ROT ROT - >> The calculator put a blank between the - and the 2 automatically. This could have been the mistake in the program. << 2 ->LIST SWAP / EVAL SWAP - 2 / DUP SQ ROT - v/ DUP2 + ROT ROT - >> << 3 PICK / SWAP ROT -2 * / DUP SQ ROT - SQRT DUP2 * ROT ROT - >> Is there a sign for SQRT on this page? When I punched the keys in the calculator itself made a blank between the - and the 2. How could I know that the calculator made this mistake? Does the HP always makes mistakes like this? How can I avoid this kind of mistakes? There might be any hope and help to rectify these short programs? RE: root of a quadratic equation - Thomas Klemm - 08-22-2015 12:03 PM Why not using PROOT? Code: \<< { 3 } \->ARRY PROOT OBJ\-> DROP \>> Cheers Thomas RE: root of a quadratic equation - tigger - 08-22-2015 05:17 PM When I type the first "\" before << I get "Invalid Syntax". Without the first "\" I get: Error "Can't find Selection. Could you write me what I did wrong? RE: root of a quadratic equation - Hlib - 08-22-2015 06:55 PM e.g. for -x^2+3x+1=0 input: -1 3 1 << 3 →ARRY PROOT OBJ→ DROP >> EVAL output: 1: -.302775637732 2: 3.30277563773 RE: root of a quadratic equation - Thomas Klemm - 08-22-2015 07:01 PM I was using tri-graphs to write the code. This makes it easy to transfer it to the calculator. HTH Thomas RE: root of a quadratic equation - Gerson W. Barbosa - 08-22-2015 07:28 PM (08-22-2015 12:03 PM)Thomas Klemm Wrote: Why not using PROOT? Well, for this example PROOT will give ugly approximations: 1 '-√2-√3' '√6' « { 3 } →ARRY PROOT OBJ→ DROP » EVAL --> 1.41421356237 1.73205080757 For exact results, in exact mode I would prefer something like « ROT NEG SWAP OVER / UNROT / 2 / SWAP OVER SQ + √ DUP2 - FACTOR UNROT + FACTOR » --> '√2' '√3' Cheers, Gerson. RE: root of a quadratic equation - Gerson W. Barbosa - 08-22-2015 07:33 PM (08-22-2015 09:41 AM)tigger Wrote: There might be any hope and help to rectify these short programs? While these aren't fixed, you can try « ROT NEG SWAP OVER / UNROT / 2. / SWAP OVER SQ + √ DUP2 - UNROT + » Not sure whether this is shorter, though. Sizewise, Thomas Klemm's suggestion above is a much better option. Regards, Gerson. RE: root of a quadratic equation - Thomas Klemm - 08-22-2015 07:35 PM (08-22-2015 09:41 AM)tigger Wrote: Is there a sign for SQRT on this page?
Quote:When I punched the keys in the calculator itself made a blank between the - and the 2. How could I know that the calculator made this mistake? To enter -2 you have to punch the [2] and then the [±] key. Cheers Thomas RE: root of a quadratic equation - Gerson W. Barbosa - 08-22-2015 08:07 PM (08-22-2015 09:41 AM)tigger Wrote: These two equations help to solve a root of a quadratic equation: * and - at the end should be - and +, respectively: << 3 PICK / SWAP ROT -2 * / DUP SQ ROT - SQRT DUP2 - ROT ROT + >> On the HP 50g, we can use << PICK3 / SWAP ROT -2 * / DUP SQ ROT - SQRT DUP2 - UNROT + >> and save a few bytes. This is 50-byte long, 5 bytes shorter than my attempt at this above. Gerson. RE: root of a quadratic equation - Thomas Klemm - 08-22-2015 08:18 PM (08-22-2015 09:41 AM)tigger Wrote: There might be any hope and help to rectify these short programs? Here's a variant from a previous thread using local variables: Code: « → a b c Cheers Thomas RE: root of a quadratic equation - Hlib - 08-22-2015 11:06 PM (08-22-2015 07:28 PM)Gerson W. Barbosa Wrote: Well, for this example PROOT will give ugly approximations: The simple way to obtain result: 'x²+(-√2-√3)*x+√6=0' SOLVEVX SIMPLIFY =>> {x=√2 x=√3} RE: root of a quadratic equation - Gerson W. Barbosa - 08-23-2015 12:43 AM (08-22-2015 11:06 PM)Hlib Wrote:(08-22-2015 07:28 PM)Gerson W. Barbosa Wrote: Well, for this example PROOT will give ugly approximations: Well, live and learn! |