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Infinite Series Problem - chazzs - 01-07-2016 05:45 AM
For my Calc III class lecture I have the following infinite series for the students:
-9 + 27/4 - 81/16 + 243/64 - 729/256 ...
This is a geometric series with the first term a = -9 and the common ratio r = -3/4.
The infinite series value is S = a/(1-r) = -9/(1-(-3/4)) = -36/7
When entered into the Prime, regardless how I enter it I get the result of +/- inf, not -36/7.
I'm entering it as the summation as k goes from 1 to infinity, of (-9)(-3/4)^(k-1). I've tried it various ways and can never get the result -36/7.
Any ideas.
C
RE: Infinite Series Problem - Didier Lachieze - 01-07-2016 06:07 AM
Did you try sum() in CAS mode?
RE: Infinite Series Problem - jte - 01-07-2016 06:34 AM
The CAS currently interprets (-9)(-3/4)^(k-1) as (-9) being given (-3/4)^(k-1) as an argument, not as implicit multiplication of (-9) and (-3/4)^(k-1).
Try using (-9)*(-3/4)^(k-1).
RE: Infinite Series Problem - chazzs - 01-07-2016 11:32 PM
So far none of the suggestions have worked, neither with the summation sign, nor the sum command. I think the problem lies with it being an alternating series and the parsing of the parentheses. The prime seems to be ignoring the parentheses around the base (-0.75)^k. Non alternating series and partial sums seem to work, but not an infinite alternating series. Still not sure what is actually happening though. Seems a little random on what is evaluated and what is no.
RE: Infinite Series Problem - Terje Vallestad - 01-08-2016 12:01 AM
(01-07-2016 11:32 PM)chazzs Wrote: So far none of the suggestions have worked, neither with the summation sign, nor the sum command. I think the problem lies with it being an alternating series and the parsing of the parentheses. The prime seems to be ignoring the parentheses around the base (-0.75)^k. Non alternating series and partial sums seem to work, but not an infinite alternating series. Still not sure what is actually happening though. Seems a little random on what is evaluated and what is no.
If you enter Σ(-9*(-3/4)^(k-1),k,1,∞) in (algebraic notation in) CAS you should get the desired result. You can also use textbook and the template and get the same result. The multiplication must be explicit between -9 and (-3/4), and as seems to be the case with most CAS functions the Angle Measure setting must be Radians.
Hope this helps
Cheers, Terje
RE: Infinite Series Problem - Tim Wessman - 01-11-2016 05:18 PM
(01-07-2016 11:32 PM)chazzs Wrote: So far none of the suggestions have worked, neither with the summation sign, nor the sum command.
Have you been able to resolve this? Indeed, you must put * between things in the CAS to avoid problems as stated.