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+--- Thread: Laplace function a bit limited (/thread-7181.html)
Laplace function a bit limited - hsauro - 11-05-2016 11:42 PM
Just got a new HP prime C series. I tried some Laplace transform derivations and the first two I picked failed, these were:
1/t
which I entered as laplace (1/t, t, s)
it returned undef
and
(1-e^{-t})/t
entered as laplace ((1-e^(-t))/t, t, s)
returned undef.
Question is have I entered the equations incorrectly or is the CAS just limited? The 1/t in particular is a standard function to get the laplace transform of, its just 1/s^2.
RE: Laplace function a bit limited - Mark Hardman - 11-06-2016 12:40 AM
On my first day of Filter Design 214 I learned:
ℒ[t] = 1/s^2
https://www.wolframalpha.com/input/?i=laplace(t,t,s)
Just saying...
Mark Hardman
RE: Laplace function a bit limited - hsauro - 11-06-2016 01:37 AM
(11-06-2016 12:40 AM)Mark Hardman Wrote: On my first day of Filter Design 214 I learned:
ℒ[t] = 1/s^2
https://www.wolframalpha.com/input/?i=laplace(t,t,s)
Just saying...
Mark Hardman
Of course I know what the Laplace transform of t is. What I wanted to know was whether the calculator knew, obviously it didn't. As I said, this was surpring for such a basic transform. It suggests to me that the Cas capability at least for Laplace transforms might be limited. I shall need to try some more.
RE: Laplace function a bit limited - Mark Hardman - 11-06-2016 01:47 AM
(11-06-2016 01:37 AM)hsauro Wrote: Of course I know what the Laplace transform of t is. What I wanted to know was whether the calculator knew, obviously it didn't. As I said, this was surpring for such a basic transform. It suggests to me that the Cas capability at least for Laplace transforms might be limited. I shall need to try some more.
No, you said the following:
(11-06-2016 01:37 AM)hsauro Wrote: The 1/t in particular is a standard function to get the laplace transform of, its just 1/s^2.
Which is demonstratively false.
The CAS is telling you that there is no standard form for:
ℒ[1/t]
WolframAlpha agrees.
https://www.wolframalpha.com/input/?i=laplace(1%2Ft,t,s)
"(no result found in terms of standard mathematical functions)"
Mark Hardman
RE: Laplace function a bit limited - hsauro - 11-06-2016 01:58 AM
(11-06-2016 01:47 AM)Mark Hardman Wrote:(11-06-2016 01:37 AM)hsauro Wrote: Of course I know what the Laplace transform of t is. What I wanted to know was whether the calculator knew, obviously it didn't. As I said, this was surpring for such a basic transform. It suggests to me that the Cas capability at least for Laplace transforms might be limited. I shall need to try some more.
No, you said the following:
(11-06-2016 01:37 AM)hsauro Wrote: The 1/t in particular is a standard function to get the laplace transform of, its just 1/s^2.
Which is demonstratively false.
The CAS is telling you that there is no standard form for:
ℒ[1/t]
WolframAlpha agrees.
https://www.wolframalpha.com/input/?i=laplace(1%2Ft,t,s)
"(no result found in terms of standard mathematical functions)"
Mark Hardman
My bad I apologize, don't know why I typed in 1/t ! Prime certainly can do t.
Anyone one reading this thread, it's a false alarm, sorry for the confusion.
RE: Laplace function a bit limited - hsauro - 11-06-2016 02:06 AM
(11-06-2016 01:58 AM)hsauro Wrote: [quote='Mark Hardman' pid='63693' dateline='1478396852']
No, you said the following:
Which is demonstratively false.
The CAS is telling you that there is no standard form for:
ℒ[1/t]
WolframAlpha agrees.
https://www.wolframalpha.com/input/?i=laplace(1%2Ft,t,s)
"(no result found in terms of standard mathematical functions)"
Mark Hardman
If any one has the power to delete threads this is one that should probably be deleted in case it inadvertently mismlead ssomeone, since the original premise is incorrect.
RE: Laplace function a bit limited - CH3791 - 11-06-2016 02:27 AM
You can delete threads yourself. Just click edit>full edit and on the top there is an option to delete.