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Pandigital e - Printable Version

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Pandigital e - Paul Dale - 12-28-2016 11:40 AM

This video presents a lovely pandigital approximation for Euler's e:






Pauli


RE: Pandigital e - Gerson W. Barbosa - 01-01-2017 12:14 AM

Speaking of pandigital approximations,

Happy '5*EXP(6)-INV(LN(1039-EXP(-LN(2^(7-√4+8)))))' !

Not so lovely, but this should evaluate (almost) nicely on the wp34s (DBLOFF).

Gerson.


RE: Pandigital e - Paul Dale - 01-01-2017 12:42 AM

I've got a nice one that doesn't use any digits:

π →HR TANH TAN⁻¹ x²

Degrees mode only. Use FIX 0 or add an IP to the end.


Pauli


RE: Pandigital e - Gerson W. Barbosa - 01-01-2017 03:32 AM

Not so accurate, but digits 1 through 9 in order (well, sort of):

'EXP(EXP(EXP(EXP(-.345678912))))-INV(π)+INV(π^π+INV(π)+e)+(π^π)^-π'


RE: Pandigital e - Paul Dale - 01-01-2017 08:32 AM

Okay, I'll use two sequential digits:

\( \lfloor 5 e^6 \rfloor \)


RE: Pandigital e - Paul Dale - 01-01-2017 08:43 AM

Or just unity but two levels of exponents:

\( \lfloor e^{10^{SINH^{-1}1}} \rfloor \)


RE: Pandigital e - Gerson W. Barbosa - 01-01-2017 10:44 AM

(01-01-2017 08:43 AM)Paul Dale Wrote:  Or just unity but two levels of exponents:

\( \lfloor e^{10^{SINH^{-1}1}} \rfloor \)

Nice one-digit one! I still can't make it without all ten of them, though:

\(\lfloor 6.538472901! \rfloor \)


RE: Pandigital e - Paul Dale - 01-01-2017 11:03 AM

(01-01-2017 10:44 AM)Gerson W. Barbosa Wrote:  \(\lfloor 6.538472901! \rfloor \)

You don't need the 01 at the end Smile


Pauli


RE: Pandigital e - Gerson W. Barbosa - 01-01-2017 11:04 AM

Or without all ten of them, twice:

'6.538472901!-EXP(-6.978245310)'


RE: Pandigital e - Gerson W. Barbosa - 01-01-2017 11:10 AM

(01-01-2017 11:03 AM)Paul Dale Wrote:  
(01-01-2017 10:44 AM)Gerson W. Barbosa Wrote:  \(\lfloor 6.538472901! \rfloor \)

You don't need the 01 at the end Smile


Pauli

I know, but the family gathering would not be complete without the patriarchs :-)