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(12C) Projectile Motion - Eddie W. Shore - 01-07-2017 05:32 PM
HP 12C: Projectile Motion, No Air Resistance: Maximum Distance (U.S. Units)
For an object that travels in a projectile motion, we can track its range (distance traveled from the beginning) and height by:
R = v^2 * sin (2 * θ)/g
H = (v^2 * (sin θ)^2) / (2 * g)
Where:
v = initial velocity
θ = initial angle
g = Earth’s gravity. For in US units, g = 32.1740468 ft/s^2.
This program uses the approximation g ≈ 32.174 ft/s^2
The projectile will have maximum range (distance) if we aim the object at 45°.
Aside: Why?
Let’s let range (R) be a function of angle (θ):
R = v^2/g * sin(2 * θ)
Find the critical points by finding the zero of the first derivative:
dR/dθ = 2 * v^2/g * cos (2 * θ)
0 = 2 * v^2/g * cos (2 * θ)
0 = cos (2 * θ)
arccos 0 = 2 * θ
π/2 = 2 * θ
θ = π/4
Now we can use the second derivative to test whether the function is at a maximum (less than 0) and minimum (more than 0) at the crucial point.
d^2 R/dθ^2 = -4 * v^2/g * sin(2 * θ)
Let θ = π/4
-4 * v^2/g * sin(2 * π/4) = -4 * v^2/g * sin(π/2) = -4 * v^2/g < 0
(We are assuming the initial velocity is positive, and g ≈ 32.174 >0)
Since the second derivative at θ = π/4 is negative, the range is at its maximum.
Note that calculus is done when the angles are measured in radians. π/2 in degrees is 90° and π/4 in degrees is 45°. (We are only concentrating on angles between 0° and 90°)
To find the maximum range and height, substitute at θ = 45° and range and height are:
R = v^2 /g
H = v^2 / (4 * g)
The time this certain projectile lasts is:
T = (v * √2) / (2 * g)
Program:
Keep in mind: this is done on the HP 12C (regular). For the HP 12C Platinum, the code for Last X is 43, 40 ([ g ] [ + ])
STEP; KEY; CODE NUMBER
01; STO 1; 44, 1
02; 2; 2
03; ÷; 10
04; LST x; 43, 36
05; √x; 43, 21
06; *; 20
07; 3; 3
08; 2; 2
09; .; 48
10; 1; 1
11; 7; 7
12; 4; 4
13; STO 0; 44, 0
14; ÷; 10
15; R/S; 31
16; RCL 1; 45, 1
17; ENTER; 36
18; *; 20
19; RCL 0; 45, 0
20; ÷; 10
21; R/S; 31
22; 4; 4
23; ÷; 10
24; GTO 00; 43, 33, 00
Input: velocity in ft/s (convert from mph to ft/s by multiplying it by 22/15)
Output:
time of projectile in seconds, [R/S]
range of projectile in feet, [R/S]
height of projectile in feet
Example:
V = 25 mph = 36.6666667 ft/s (110/3)
Output:
Time: 0.81 sec, Range: 41.79 ft, Height: 10.45 ft
Source: Rosenstein, Morton. Computing With the Scientific Calculator Casio: Tokyo, Japan. 1986. ISBN-10: 1124161430