HP-Prime CAS versus TI-CAS (TI68k & TI-nspire) - Printable Version +- HP Forums (https://www.hpmuseum.org/forum) +-- Forum: HP Calculators (and very old HP Computers) (/forum-3.html) +--- Forum: HP Prime (/forum-5.html) +--- Thread: HP-Prime CAS versus TI-CAS (TI68k & TI-nspire) (/thread-7552.html) HP-Prime CAS versus TI-CAS (TI68k & TI-nspire) - compsystems - 01-10-2017 08:05 PM Robotic translator = ( Why do I consider the HP-Prime CAS better than the TI-CAS (TI68k & TI-nspire)? 1: because it allows me to better manipulate algebraic expressions, observing intermediate steps. Ideal for creating step-by-step programs without having to create subroutines or conversion to strings to show intermediate steps (Although if the HP-Prime CAS did not rewrite some of the expressions would be much better), It is customary to see on mathbook, the inequalities, the numbers to the right side and the symbolic expressions to the left side. 0 > (x ^ 2 + x-6) == (x ^ 2 + x-6) < 0 Graphic comparison Code comparison HP-PRIME CAS PHP Code: #cas    testInequality1():=    begin     local expr0;     print;     print("step1:");     expr0 := '(3*x^2-2*x-2) < (2*x^2-3*x+4)';     //expr0 :=  (3*x^2-2*x-2) < (2*x^2-3*x+4);     print(string(expr0));      print("");     print("step2: +(-2*x^2)");     expr0 := expr0 + -2*x^2;     print(string(expr0));      expr0 := simplify(expr0); // Requires a sentence more of simplification.     print("simplify → " +expr0);     print("");     print("step3: +(3*x)");     expr0 := expr0 + 3*x;     print(string(expr0));      expr0 := simplify(expr0);      print("simplify → "+expr0);     print("");     print("step4: +(-4)");     expr0 := expr0 + -4;     print(string(expr0));      expr0 := simplify(expr0);      print("simplify → "+expr0);     print("");     return expr0;       end;#end  TI-CAS PHP Code: // ti68kinequali()Prgm Local expr0 ClrIO Disp "step1: " 3*x^2-2*x-2 < 2*x^2-3*x+4 → expr0 Disp expr0 Disp "step2: +(-­2*x^2)" expr0 + ­2*x^2 → expr0 Disp expr0 Disp "step3: +3*x" expr0 + 3*x → expr0 Disp expr0 Disp "step4: +(-­4)": Pause expr0 + -­4 → expr0 Disp expr0EndPrgm  Disadvantages, does not handle simplifying operations and others on inequalities. I would like to know your options Why do you consider that one is better or the other?