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Happy Pi Day! - Printable Version

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RE: Happy Pi Day! - Gerson W. Barbosa - 03-18-2017 09:17 PM

(03-18-2017 03:43 AM)Joe Horn Wrote:  That's 433 digits (217 digits over 216 digits) that returns 435 digits of pi. Converting the above into a mnemonic is left as an exercise for the student. Smile

Speaking of mnemonics, I think I've found a good one for 20. Just in case I forget about the number :-)

\({e}^{\pi }-\pi +\frac{81}{89998-{10}^{5}\cdot \left ( {\frac{81}{89998}} \right )^{2}}\)


RE: Happy Pi Day! - pier4r - 03-28-2017 10:30 AM

(03-14-2017 01:14 AM)Gerson W. Barbosa Wrote:  -cut-

How does one split a number to let it be multiline on the 50g? Is there a built in function or a third party function or one needs to take the number as string and then break it down with a little userRPL program? (the solution of Gerson I suppose, looking at the code)


RE: Happy Pi Day! - Joe Horn - 03-28-2017 11:59 AM

(03-28-2017 10:30 AM)pier4r Wrote:  How does one split a number to let it be multiline on the 50g? Is there a built in function or a third party function or one needs to take the number as string and then break it down with a little userRPL program?

One very fast solution is the "LNViewer" library by Christophe Laluc, which you can read about and download HERE. I use it for viewing long integers and outputs from the LongFloat library. Be sure to read LNViewer's documentation, because how to use it is non-obvious.


RE: Happy Pi Day! - pier4r - 03-28-2017 09:23 PM

(03-28-2017 11:59 AM)Joe Horn Wrote:  
(03-28-2017 10:30 AM)pier4r Wrote:  How does one split a number to let it be multiline on the 50g? Is there a built in function or a third party function or one needs to take the number as string and then break it down with a little userRPL program?

One very fast solution is the "LNViewer" library by Christophe Laluc, which you can read about and download HERE. I use it for viewing long integers and outputs from the LongFloat library. Be sure to read LNViewer's documentation, because how to use it is non-obvious.

It is a neat solution. Thanks!