challenge - Printable Version +- HP Forums ( https://www.hpmuseum.org/forum)+-- Forum: Not HP Calculators ( /forum-7.html)+--- Forum: Not remotely HP Calculators ( /forum-9.html)+--- Thread: challenge ( /thread-9505.html) |

challenge - Don Shepherd - 11-16-2017 01:03 AM
Without using a CAS or the Internet, how many factors does this number have: 200,560,490,130? RE: challenge - Paul Dale - 11-16-2017 01:20 AM
Prime factorisation by hand didn't take long and it revealed 11 factors. Each can be present or absent for each factor so 2 ^{11} = 2048 in total.Pauli RE: challenge - Don Shepherd - 11-16-2017 01:30 AM
(11-16-2017 01:20 AM)Paul Dale Wrote: Prime factorisation by hand didn't take long and it revealed 11 factors. Each can be present or absent for each factor so 2Congratulations Pauli! 200,560,490,130 is the product of the first 11 prime numbers. To find the total number of factors of a number, determine the numbers prime factors, then add 1 to each exponent and then multiply those numbers together: 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 2,048 |