Bug? int(abs(sin(2*pi*x)),x=0..1) [SW 8151]
#1
Hello,

Maybe this was reported somewhere already (didn't find a posting).

When evaluating int( abs(sin(2*pi*x)), x=0..1 )
I get the incorrect result 0.

This doesn't occur when using cosine: int( abs(cos(2*pi*x)), x=0..1 ),
or by rewriting the expression: int( abs(sin(x)), x=0..2*pi )/(2*pi);
both yield 2/pi.

   

Greetings
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#2
Not reported anywhere I've seen. Thanks! Have passed it on.
TW

Although I work for HP, the views and opinions I post here are my own.
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