Polar and Rectangular conversion

[ijabbott]

(07-26-2018 07:01 PM)DrD Wrote:  polar_coordinates(-1,-1) ==> [sqrt(2),(3/4)*π]
polar_coordinates([-1,-1]) ==> [sqrt(2),(-3/4)*π]

I was confused why those gave different results, but it's a typo. They give the same (expected) result: \( \begin{bmatrix} \sqrt 2& -\frac{3}{4}\ast\pi \end{bmatrix} \).