Summation on HP 42S

[Thomas Klemm]

(09-26-2018 04:09 PM)pier4r Wrote:  I do for loop and then I benchmark things to be faster as I am lazy.

Or then you just have the compiler figure out the closed formula for you.

Cheers
Thomas

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Here's the code for \(\sum_{x=1}^n x^2 - 3 x = \frac{1}{3} (n - 4) n (n + 1)\).