Solving x^y=y^x

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Solving x^y=y^x

10-24-2018, 07:45 PM (This post was last modified: 10-24-2018 07:46 PM by sasa.)

Post: #4

sasa

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RE: Solving x^y=y^x

(10-24-2018 07:21 PM)Albert Chan Wrote: solve(subst(x^y=y^x, y=t*x), x) ==> [ t^(1/(t-1)) ]

Yes, but without substitution hint, it seems it cannot conclude that is needed.
Perhaps with another function?

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Messages In This Thread

Solving x^y=y^x - sasa - 10-24-2018, 06:06 PM

RE: Solving x^y=y^x - Dieter - 10-24-2018, 07:37 PM

RE: Solving x^y=y^x - sasa - 10-24-2018, 08:45 PM

RE: Solving x^y=y^x - Erwin - 10-26-2018, 04:54 PM

RE: Solving x^y=y^x - Erwin - 10-28-2018, 08:51 PM

RE: Solving x^y=y^x - sasa - 10-24-2018 07:45 PM

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