(12C) Resistors in Parallel

[Albert Chan]

Hi Gamo

Dieter had a better program, with more accuracy by doing R = R1 R2 / (R1 + R2)

Quote:What is the total with 4 resistors in parallel?
50, 65, 120 and 250

There is no need for more code. Just keep running each pair in parallel.

Parallel of 50, 65, R = 50*65/(50+65) = 28.261
"Add" 120, R = 120*28.261/(120+28.261) = 22.874
"Add" 250, R = 250*22.874/(250+22.874) = 20.957 (total of 4 resister in parallel)

Quote:1st resistor is 50 and my desire total is 28.2608
What is the 2nd resistor value?

Again, no need for more code. Remove a resister from total R, just negate the resister.

R1 = -50*28.2608/(-50+28.2608) = 65.000