Little math problem(s) December 2018
|
12-19-2018, 08:54 PM
(This post was last modified: 12-26-2018 09:19 PM by pier4r.)
Post: #1
|
|||
|
|||
Little math problem(s) December 2018
Given a random positive integer N, compute the sum S of its digits (for example 50 -> S = 5 + 0 = 5). Subtract this sum from N, thus getting the result "R=N-S".
What is the smallest divisor greater than 1 that can divide evenly every R so computed? Why is it so? Wikis are great, Contribute :) |
|||
« Next Oldest | Next Newest »
|
Messages In This Thread |
Little math problem(s) December 2018 - pier4r - 12-19-2018 08:54 PM
RE: Little math problem December 2018 - Thomas Klemm - 12-19-2018, 09:20 PM
RE: Little math problem December 2018 - pier4r - 12-19-2018, 10:39 PM
|
User(s) browsing this thread: 1 Guest(s)