dynamical list problem

[Albert Chan]

(01-03-2019 02:11 PM)peacecalc Wrote:  Now the first velocity was v = (1m + 2m + 1m +(3-2)m)/(3s + (1/3)s) = 1,5 m/s,
the second was: v = (2m+3m)/(1s + 1s) = 2,5 m/s.

I think "the second" meant last 5m speed, from your data: 5 {1 2 1 3 2}

Note: the word velocity included direction. So, if you run in a 5m circle, 5m averaged velocity = 0 m/s