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(12C) log1p function
02-01-2019, 07:07 AM
Post: #9
RE: (12C) log1p function
(01-31-2019 01:10 AM)Albert Chan Wrote:  log1p(X) = ln(1 + X) + (X + 1 - 1 - X) / (X + 1)

That should be

ln(1 + X) - (X + 1 - 1 - X) / (X + 1)

as the [CHS] in your instructions indicate, and then it's the same formula as Dieter's.

Cheers, Werner

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Messages In This Thread
(12C) log1p function - Albert Chan - 01-31-2019, 01:10 AM
RE: (12C) log1p function - Thomas Klemm - 01-31-2019, 04:08 AM
RE: (12C) log1p function - Paul Dale - 01-31-2019, 05:48 AM
RE: (12C) log1p function - Dieter - 01-31-2019, 08:45 AM
RE: (12C) log1p function - Albert Chan - 01-31-2019, 09:42 AM
RE: (12C) log1p function - Dieter - 01-31-2019, 09:43 PM
RE: (12C) log1p function - Albert Chan - 01-31-2019, 10:55 PM
RE: (12C) log1p function - Werner - 02-01-2019 07:07 AM
RE: (12C) log1p function - Albert Chan - 02-01-2019, 12:30 PM
RE: (12C) log1p function - Thomas Klemm - 02-02-2019, 12:28 PM
RE: (12C) log1p function - Albert Chan - 02-10-2019, 09:08 AM
RE: (12C) log1p function - Albert Chan - 02-10-2019, 02:19 PM



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