(12C Platinum) Zero of Function
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02-03-2019, 01:31 PM
Post: #2
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RE: (12C Platinum) Secant Method
Hi, Gamo
I thought Secant's method required 2 points, thus 4 variables: (x0, f0), (x1,f1) Interpolate the line to (x2, 0): Slope = (f1-f0)/(x1-x0) = (f1-0)/(x1-x2) --> x2 = x1 - f1/(f1-f0) * (x1-x0) The method only use the most recent 2 points. There should be some updates: x0,f0,x1,f1 = x1,f1,x2,f(x2) For your code, I did not see f0 anywhere. Also, your code seems to start the equation at line 023. |
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Messages In This Thread |
(12C Platinum) Zero of Function - Gamo - 02-03-2019, 10:34 AM
RE: (12C Platinum) Secant Method - Albert Chan - 02-03-2019 01:31 PM
RE: (12C Platinum) Secant Method - Dieter - 02-03-2019, 05:57 PM
RE: (12C Platinum) Secant Method - Gamo - 02-04-2019, 01:00 AM
RE: (12C Platinum) Zero of Function - Dieter - 02-04-2019, 05:19 PM
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