What changes were made for 2.023 of Android Free42?

[Nigel (UK)]

(02-10-2019 02:06 AM)Jlouis Wrote:  <snip>
This is very interesting...

I am not a mathematician (yet), so may I ask opinions from Gerson, Joe, Ed, Dieter, and others about this subject?

I am not a mathematician either! I think that it is correct to say that \(0^0\) is undefined. Consider the function
$$f(x)=x^{-1/\ln(x)}.$$
As \(x\to 0^+\) both \(x\) and the power it is raised to tend to zero, so it is tempting to write \(f(0)\) as \(0^0\). But for all positive values of \(x\), \(f(x)\) is equal to \(1/e\), so
$$\lim_{x\to 0^+}f(x)={1\over e}.$$
So to give a value to the expression \(0^0\) it is necessary to know how the limit was reached. Because of this the expression itself is indeterminate.

Nigel (UK)