HP-29C: 98 Program Steps, So, why not an even 100?

[teenix]

(08-31-2019 02:18 AM)bshoring Wrote:  So that tells me there is a small memory space set aside to accommodate the 21 Nj registers of 2 digits. I believe 2 digits can be stored in one byte, so if there are 21, then it seems to me they set aside 3 full (7 byte) registers to hold the 21 values.

My two cents...

It looks like the 38 has more than 32 RAM registers, but I'm not sure how many registers they actually have. I'll have to adjust the emulator memory size.

For the 38E The Nj numbers are stored from RAM address 32 onward. For the 38C these are stored starting at address 7.

cheers

Tony