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Puzzle: sequence without multiples of 3
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Puzzle: sequence without multiples of 3
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Puzzle: sequence without multiples of 3
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09-14-2019, 12:30 AM
(This post was last modified: 09-14-2019 12:39 AM by Thomas Okken.)
Post: #5
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RE: Puzzle: sequence without multiples of 3
f(n) = floor((n-1)*1.5)+1
This wouldn't be much of a puzzle if the most obvious formula happened to be the solution, but I thought I'd get it out of the way. As a baseline, if you will. UPDATE to add the answer to the second question: f(10^6) = 1,499,999 |
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| Messages In This Thread |
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Puzzle: sequence without multiples of 3 - Albert Chan - 09-13-2019, 07:05 PM
RE: Puzzle: sequence without multiples of 3 - Voldemar - 09-13-2019, 08:57 PM
RE: Puzzle: sequence without multiples of 3 - Voldemar - 09-13-2019, 09:02 PM
RE: Puzzle: sequence without multiples of 3 - Albert Chan - 09-13-2019, 09:43 PM
RE: Puzzle: sequence without multiples of 3 - Thomas Okken - 09-14-2019 12:30 AM
RE: Puzzle: sequence without multiples of 3 - John Keith - 09-14-2019, 12:54 AM
RE: Puzzle: sequence without multiples of 3 - Albert Chan - 09-14-2019, 01:01 AM
RE: Puzzle: sequence without multiples of 3 - Gerald H - 09-14-2019, 05:37 AM
RE: Puzzle: sequence without multiples of 3 - Albert Chan - 09-14-2019, 08:29 AM
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