CAS: Hyperbolic Functions, assume (Beta)

[Stevetuc]

(11-06-2019 08:29 PM)parisse Wrote:  You can convert yourself like this:
subst(exp(x)+exp(-x),exp,cosh+sinh)

It would be useful if the cas handled such cases using simplify

eg

Code:


simplify(i*e^((−i)*th)+(−i)*e^(i*th))/2

Gives result

Code:


(i*e^((−i)*th)+(−i)*e^(i*th))/2

Rather than the anticipated result sin(th)
One would have to create a lot of manual subst to workaround all the trig exp forms


And this integral

Code:


10/(√(2*π))*int(e^((-(I))*w*t),t,(-tt)/2,tt/2)

gives result

Code:


(5*i*√(2*π)*e^((−i)*tt*w/2)+(-5*i)*√(2*π)*e^(i*tt*w/2))/(π*w)

But it would be clearer to the user if the result simplified to the equivalent sinc() function