CAS: Hyperbolic Functions, assume (Beta)

[CyberAngel]

(12-09-2019 08:25 AM)Stevetuc Wrote:  Just found that

Code:


simplify(sincos((i*e^((-(i))*th)+(-(i))*e^(i*th))/2))

Gives the much nicer result

Code:


sin(th)

And

Code:


simplify(sincos((5*i*√(2*π)*e^((-(i))*tt*w/2)-5*i*√(2*π)*e^(i*tt*w/2))/(π*w)))

Gives

Code:


10*√(2*π)*sin(tt*w/2)/(π*w)

So it would be handy if the cas had an option to return complex exp results in sincos form, so that simplify could do the above automatically

Assign 'sincos' into a [key] in the User mode