(41) Exponentiation & Residue Reduction
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04-06-2020, 01:31 PM
(This post was last modified: 04-26-2022 04:13 PM by SlideRule.)
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(41) Exponentiation & Residue Reduction
Pages 341 & 344 from Number Theory in Science and Communication, Second Enlarged Edition, © Sprinler·Veriag Berlin Heidelberg 1984 and 1986, ISBN 978-3-662-22246-1 (eBoook)
"A. A Calculator Program for Exponentiation and Residue Reduction We list here a program for calculating the least nonnegative remainder of aⁿ modulo m on a Hewlett-Packard 41C or 41CV pocket calculator. In other words, in our acute bracket notation, the calculator calculates The 3 variables, the base a, the exponent n and the modulus m are entered into the calculator in that order. To call the program, which is labeled "AN", from storage, one presses GTO "AN" . To calculate, say, {2³⁴⁰}₃₄₁ , one proceeds by pressing the following buttons: 2 ENTER 340 ENTER 341 To start the program, one presses R/S After 2 seconds the HP 41 display shows in rapid succession 8. 6. 4. 2. This is the binary decomposition of the exponent 340. Check: 28 + 26 + 24 + 22 = 340. Check! Next, the computer will start the necessary repeated squarings and reductions modulo 341, which will take about 7 seconds. Then the display will show the end result, a 1 (without a decimal point!). Thus, {2³⁴⁰)₃₄₁ = 1 . In other words, 341 is a pseudoprime to the base 2. Similarly, after pressing 2, ENTER, 170, ENTER, 341, R/S, the display shows in succession: 7. 5. 3. 1. 1 where that last display (the 1 without the decimal point) tells us that {2¹⁷⁰}₃₄₁ = 1 . Proceeding in the same manner, we find {2⁸⁵}₃₄₁ = 32 . i.e., 341 is not a strong pseudoprime to the base 2. Also, by using 3 as a base we find {3³⁴⁰}₃₄₁ = 56 . Thus, 341 is certainly not an absolute pseudoprime (Carmichael number). However, for the modulus 2821, we find {2²⁸²⁰}₂₈₂₁ = {3²⁸²⁰}₂₈₂₁ = 1 . two of the many steps necessary to show that 2821 is an absolute pseudoprime or a Carmichael number Note that our little calculator with a limited accuracy and a 10-digit display, in calculating (3²⁸²⁰}₂₈₂₁, has coped with a number having 1346 decimal digits! This has been made possible by the frequent intermediate modulo reduction that the program employs. Listing for "AN" Comment Step Code call program 01 LBL "AN" decimal point 02 SF 29 store modulus 03 STO 18 get exponent 04 RDN store exponent 05 STO 17 get base 06 RDN store base 07 STO 16 constant 08 2 store 2 09 STO 01 take logarithm 10 LN store log 11 STO 15 display no fractions 12 FIX 0 constant 13 1 store 1 14 STO 14 constant 15 0 store 0 16 STO 02 subroutine for calculating 17 LBL 10 binary representation of n 18 RCL 17 19 LN 20 RCL 15 21 / add small constant to 22 0.000000001 avoid inaccurate rounding 23 + 24 INT 25 ENTER 26 ST- IND 01 display the binary 27 PSE exponents of n 28 1 29 ST+ 01 30 RDN 31 STO IND 01 32 2 33 x <> y 34 y^x 35 ST- 17 36 RCL 17 binary representation 37 x = 0? of n completed? 38 GTO 11 39 GTO 10 subroutine for executing 40 LBL 11 repeated squaring 41 RCL IND 01 42 x = 0? 43 GTO 12 44 RCL16 45 RCL 18 46 2 47 / 48 x < > y 49 x > y? 50 XEQ 16 51 x² 52 RCL 18 take remainder 53 MOD modulo n 54 STO 16 55 1 56 ST- IND 01 57 GTO 11 subroutine for cal- 58 LBL 12 culating intermediate 59 RCL 16 squaring results 60 ST* 14 61 RCL 14 62 RCL 18 63 MOD 64 STO 14 65 1 66 ST- 01 67 RCL 01 68 2 69 x = y? 70 GTO 13 71 GTO 11 72 LBL 16 73 RCL 18 74 - 75 RTN Subroutine for 76 LBL 13 recalling and 77 RCL 14 displaying residue 78 CF 29 display residue 79 STOP ready to start over 80 GTO "AN" 81 RTN 82 END" BEST! SlideRule |
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(41) Exponentiation & Residue Reduction - SlideRule - 04-06-2020 01:31 PM
RE: (41) Exponentiation & Residue Reduction - Werner - 05-08-2020, 01:58 PM
RE: (41) Exponentiation & Residue Reduction - Albert Chan - 05-11-2020, 02:55 PM
RE: (41) Exponentiation & Residue Reduction - Thomas Klemm - 04-26-2022, 03:17 AM
Errata: (41) Exponentiation & Residue Reduction - Thomas Klemm - 04-26-2022, 10:59 AM
Errata: (41) Exponentiation & Residue Reduction - Thomas Klemm - 04-26-2022, 04:05 PM
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