Integral Fail
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08-15-2020, 04:38 AM
Post: #9
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RE: Integral Fail
Here comes the problem that always puts me in difficulty. If I set CAS without "use i to factor polynomials" I get:
sqrt((x-1)^2) -> abs(x-1) and the integral int(abs(x-1)^(8/3),x) takes the form proposed by Albert Chan. However, if I set CAS with "use i to factor polynomials", the result takes the form of "robmio" and, for negative "x" values, the result of the integral gives a complex number. So what is the correct result? |
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Messages In This Thread |
Integral Fail - lrdheat - 08-14-2020, 03:44 AM
RE: Integral Fail - robmio - 08-14-2020, 01:06 PM
RE: Integral Fail - robmio - 08-14-2020, 01:18 PM
RE: Integral Fail - Arno K - 08-14-2020, 01:34 PM
RE: Integral Fail - robmio - 08-14-2020, 01:50 PM
RE: Integral Fail - Albert Chan - 08-14-2020, 03:47 PM
RE: Integral Fail - lrdheat - 08-15-2020, 01:44 AM
RE: Integral Fail - Albert Chan - 08-15-2020, 04:45 AM
RE: Integral Fail - lrdheat - 08-15-2020, 02:03 AM
RE: Integral Fail - robmio - 08-15-2020 04:38 AM
RE: Integral Fail - lrdheat - 08-15-2020, 05:20 AM
RE: Integral Fail - Albert Chan - 08-15-2020, 11:44 AM
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