[WP-34S] DEG and RAD - diffs

[Thomas Klemm]

\[\sinh(x) = \frac{(e^{x}-1)(e^{x}+1)}{2 e^{x}} = 2\cdot\frac{e^{\frac{x}{2}}-e^{-\frac{x}{2}}}{2}\cdot\frac{e^\frac{x}{2}+e^{-\frac{x}{2}}}{2} = 2\cdot\sinh(\frac{x}{2})\cdot\cosh(\frac{x}{2})\]

How do you avoid infinite recursion?
Or do you calculate \(e^x-1\) directly without extinction for small x?

Cheers
Thomas

PS: I should probably just have a look at the code.