Randomize a List problem

[Wes Loewer]

(09-15-2020 01:00 AM)Albert Chan Wrote:  For a list of 3 items, we have 3! = 6 permutations.
But, your suggested shuffling can have 3*3*3 = 27 ways.

I was just about to point out the same thing, implying that the probabilities are not all equal. Just for fun, here's my attempt at randomizing a list with equal probabilities.

<< { } 1. PICK3 SIZE START RAND + NEXT SWAP 2. ->LIST TRAN SORT TRAN 2. GET >>