Improper integral

[Mark Hardman]

(06-11-2014 07:01 PM)HP67 Wrote:  The 50g says (21.01127123, -.734731565365) if my understanding matches ndzied1's. Which looks pretty close to Wolfram.

Why does the op say it should be 75/4?

The asymptote is at x=1, I'm not sure why the OP thinks there would be a real solution in the interval 0..1.

   

For a reasonable endpoint, the improper integral (1..33) we get a solution of exactly 20.

   

This requires we use fractional powers in CAS rather than nthroot. I thought those issues had been resolved in the latest release. I guess not.