Improper integral

[Mark Hardman]

(06-11-2014 10:46 PM)Onkel Otto Wrote:  It simply depends on your Real/Complex setting :

I'm still trying to wrap my mind around how we arrive at 75/4 for the "real" result.

Graphing the real and imaginary portions of the function reinforces the need to integrate over two intervals: 0..1 and 1..33.

   

As posted above, the interval between 1 and 33 gives us an exact real answer of 20. The interval between 0 and 1 gives us an approximate imaginary answer of 1.01127 - 0.734732i. The magnitude of this imaginary number is exactly 5/4.

   

The question remaining in my mind is: Why is the magnitude of the integration between 0 and 1 treated as a negative value? -(5/4)+20=75/4.

(06-11-2014 10:46 PM)Onkel Otto Wrote:  > I need professional help.

That's GAS (Gear Acquisition Syndrome) ! ... I do know, what I'm talking about :-).

If I tell my wife that I've got GAS, she's going to reply, "So, what else is new?"

Maybe I have CAS (CAS Calculator Acquisition Syndrome).