[SOLVED] DSRN (dog slow roman numerals)

[kakima]

(06-15-2014 07:29 PM)Thomas Klemm Wrote:  But then 4 + { 1 2 3 } = { 5 6 7 }.

Actually it's { 4 1 2 3 }. At least it's consistent in that + adds an element to the list. Well, that's not quite right. What's { { 1 1 } { 2 4 } { 3 9 } } + { 4 16 } ? I initially expected { { 1 1 } { 2 4 } { 3 9 } { 4 16 } } but got { { 1 1 } { 2 4 } { 3 9 } 4 16 } instead. I suppose an argument could be made either way...

Quote:I still think this was the worst decision when designing RPL.

I don't know whether I would call it the worst, but it's certainly near the top of my list.

Also note that the same commutativity violation occurs with STO+ when the variable holds a list or a string.