Solve with integrating an implicit function

[Alberto Candel]

(06-22-2014 06:31 AM)parisse Wrote:  See above, you don't have enough control on evaluation to be able to use fsolve, because of the embedded fsolve and integration inside. They will generate errors, that are trapped, and after a finite number of errors, fsolve will return with [].

thank you. I am still curious about the difference between solve and fsolve for polynomials. Is there a reference that you may provide?