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mini challenge: find the smallest cosine of an integer
10-21-2021, 01:09 PM
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RE: mini challenge: find the smallest cosine of an integer
(10-21-2021 12:01 PM)Albert Chan Wrote:  With convergents fully reduced, even numerator guaranteed odd denominator.

2 neighboring convergents, p1/q1, p2/q2, we have

p1*q2 - p2*q1 = ± 1       // or, gap = |p1/q1 - p2/q2| = 1/|q1*q2|

If g = gcd(p1,q1) ≠ 1, RHS must be multiples of g, contradict above identity.
Thus, convergents always fully reduced.
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RE: mini challenge: find the smallest cosine of an integer - Albert Chan - 10-21-2021 01:09 PM



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