Embarrassed to ask
|
07-16-2014, 02:35 PM
Post: #7
|
|||
|
|||
RE: Embarrassed to ask
(07-16-2014 02:02 PM)Thomas Radtke Wrote:(07-16-2014 01:48 AM)lrdheat Wrote: Why is -8^(2/3)=-4 instead of 4?It is a convention to have the unary minus as a shortcut for (your example) 0-8^(2/3). Hmmh, AFAIK the convention is the unary minus corresponds to a multiplication times (-1). So, in this case, -8^(2/3) = (-1)*8^(2/3) = (-1)*4 = -4. d:-) |
|||
« Next Oldest | Next Newest »
|
Messages In This Thread |
Embarrassed to ask - lrdheat - 07-16-2014, 01:48 AM
RE: Embarrassed to ask - Waon Shinyoe - 07-16-2014, 02:08 AM
RE: Embarrassed to ask - Joe Horn - 07-16-2014, 03:48 AM
RE: Embarrassed to ask - John R - 07-16-2014, 06:01 AM
RE: Embarrassed to ask - Didier Lachieze - 07-16-2014, 06:53 AM
RE: Embarrassed to ask - jebem - 07-16-2014, 07:48 PM
RE: Embarrassed to ask - Mark Hardman - 07-16-2014, 08:38 PM
RE: Embarrassed to ask - jebem - 07-16-2014, 08:57 PM
RE: Embarrassed to ask - John R - 07-16-2014, 09:43 PM
RE: Embarrassed to ask - jebem - 07-17-2014, 06:45 AM
RE: Embarrassed to ask - Thomas Radtke - 07-16-2014, 02:02 PM
RE: Embarrassed to ask - walter b - 07-16-2014 02:35 PM
RE: Embarrassed to ask - Thomas Radtke - 07-16-2014, 05:07 PM
RE: Embarrassed to ask - walter b - 07-16-2014, 09:08 PM
RE: Embarrassed to ask - lrdheat - 07-16-2014, 02:53 PM
RE: Embarrassed to ask - Thomas Radtke - 07-16-2014, 05:11 PM
|
User(s) browsing this thread: 2 Guest(s)