Incorrectly calculated integral.
|
05-22-2023, 08:35 PM
Post: #6
|
|||
|
|||
RE: Incorrectly calculated integral.
(05-21-2023 01:56 PM)Albert Chan Wrote: Cas> simplify(sqrt(-(2+sqrt(3))/4)) → (i*√2+(−i)*√6)/4 ≈ -0.259*i ??? Hi, parisse It seems sqrt of positive argument is correctly simplified. If argument is negative, perhaps simplify sqrt patch is simply pull out i ? Cas> simplify(sqrt((2+sqrt(3))/4)) * i → (√2+√6)/4 * i ✔ |
|||
« Next Oldest | Next Newest »
|
Messages In This Thread |
Incorrectly calculated integral. - hp-zl - 05-20-2023, 06:00 PM
RE: Incorrectly calculated integral. - parisse - 05-20-2023, 08:00 PM
RE: Incorrectly calculated integral. - hp-zl - 05-21-2023, 07:25 AM
RE: Incorrectly calculated integral. - Albert Chan - 05-21-2023, 01:56 PM
RE: Incorrectly calculated integral. - Albert Chan - 05-22-2023 08:35 PM
RE: Incorrectly calculated integral. - parisse - 05-22-2023, 07:26 PM
RE: Incorrectly calculated integral. - parisse - 05-23-2023, 05:13 AM
|
User(s) browsing this thread: 3 Guest(s)