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(15C) Fibonacci Numbers
08-08-2023, 11:44 AM (This post was last modified: 08-08-2023 12:45 PM by Albert Chan.)
Post: #9
RE: (15C) Fibonacci Numbers
(08-08-2023 11:05 AM)Werner Wrote:  perhaps better

F(n) ≈ 2*(0.2+√0.2)^n / (0.4^n*√20)

We might as well combine the constant, with *same* relative error as √20

2 / √20 = √20 / 10

F(n) ≈ (0.2+√0.2)^n / 0.4^n * √0.2

Scale √0.2 last, within n = 0 .. 49, rounded, only F(48) was off by 1
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Messages In This Thread
(15C) Fibonacci Numbers - Eddie W. Shore - 03-23-2017, 03:22 AM
RE: (15C) Fibonacci Numbers - Albert Chan - 08-07-2023, 10:09 PM
RE: (15C) Fibonacci Numbers - Werner - 08-08-2023, 11:05 AM
RE: (15C) Fibonacci Numbers - Albert Chan - 08-08-2023 11:44 AM
RE: (15C) Fibonacci Numbers - Thomas Klemm - 08-06-2023, 11:06 AM
RE: (15C) Fibonacci Numbers - Joe Horn - 08-06-2023, 04:49 PM
RE: (15C) Fibonacci Numbers - Thomas Klemm - 08-06-2023, 03:16 PM
RE: (15C) Fibonacci Numbers - Thomas Klemm - 08-07-2023, 10:49 PM
RE: (15C) Fibonacci Numbers - Werner - 08-08-2023, 12:06 PM



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