Accuracy summation question

[byoung]

(09-08-2023 01:38 AM)Gerson W. Barbosa Wrote:  

(09-07-2023 08:29 PM)byoung Wrote:  OK, this is probably a dumb question, but how are you guys getting such large exponents? Mine maxes out at E499.

Just using property of logarithms.

Sum(n=1,2000,log(n)) = 5735.52065052 (hp 50g)

-> 2000! 10^0.520652*10^5735

2000! = 3.31627(487045)*10^5735

Thanks. I just thought you had discovered some way to put the calculator into a high-precision mode, which I didn't think was possible.