HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x'
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11-07-2023, 09:30 PM
(This post was last modified: 11-08-2023 08:36 PM by Gil.)
Post: #5
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RE: HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x'
About the last answer
int(a^x)=a^x/ln(a) to be better formulated, with x>0: int(a^x)=a^x/ln(a) for a≠0 int(a^x)=constant, else (for a=0) ? Regarding that "stupid" function 0^X, it seems to be defined for X>0. Note that the area (zero!) is correct when setting real bounds and then the numerical calculation is requested (—>NUM) with the HP50G, but not with the EVAL command. But if you put bounds like variables named a and b, you won't get the expected 0 value with the HP50G, supposing of course x>0 (or the infinity when x<0). |
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Messages In This Thread |
HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x' - Gil - 11-06-2023, 05:05 PM
RE: HP50 : integral of '0^x' gives induly '?` - rawi - 11-07-2023, 02:38 PM
RE: HP50 : integral of '0^x' gives induly '?` - rawi - 11-07-2023, 03:11 PM
RE: HP50 : integral of '0^x' gives induly '?` - klesl - 11-07-2023, 03:28 PM
RE: HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x' - Gil - 11-07-2023 09:30 PM
RE: HP50 : integral of '0^x' gives induly '?` - klesl - 11-08-2023, 07:52 AM
RE: HP50 : integral of '0^x' gives induly '?` - Gil - 11-08-2023, 09:14 AM
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