Improper Integrals with the HP-15C LE & CE

[Commie]

(11-14-2023 03:09 PM)Werner Wrote:  That defines the function x/(sqrt(1)), which is just x. You can just use RTN then.
If you integrate that from 0 to 2 (not 1), you indeed get 2 right away, of course.

Werner

My code defines 1/sqrt(x) and is strictly integrated between 0 and 1 and gives 2.0000 the answer.