Improper Integrals with the HP-15C LE & CE

[DavidM]

(11-17-2023 09:11 PM)Voldemar Wrote:  HP 50g
1,99998390078

Other results on a 50g:

\begin{array}{clrr}
\hline
{\textbf{FIX}} & {\textbf{Rounded Result}} & {\textbf{Actual Result}} & {\textbf{IERR}} \\
\hline
0 & 2. & 1.86741548121 & 1.80693901574 \\
1 & 1.9 & 1.86741548121 & .180693901574 \\
2 & 1.98 & 1.98343207731 & 1.97334339834E-2 \\
3 & 1.999 & 1.99894753972 & 1.99831015657E-3 \\
4 & 1.9999 & 1.99987053054 & 1.99978859323E-4 \\
5 & 1.99998 & 1.99998381632 & 1.9999735715E-5 \\
6 & 1.999984 & 1.99998390078 & -1.9999735715E-6 \\
7 & 1.9999839 & 1.99998390078 & -1.9999735715E-7 \\
8 & 1.99998390 & 1.99998390078 & -1.9999735715E-8 \\
9 & 1.999983901 & 1.99998390078 & -1.9999735715E-9 \\
10 & 1.9999839008 & 1.99998390078 & -1.9999735715E-10 \\
11 & 1.99998390078 & 1.99998390078 & -1.9999735715E-11 \\
\end{array}

So whichever method is used in the 50g, it doesn't appear that there's much value trying to go above FIX 6 for the display mode. At least for this example. I'll leave it to those much more knowledgeable than me for what this actually means in practice.