HP 48GX Collector’s Edition (merged) - please don't start two threads

[Gil]

If 0^0 is or were to be defined as 1, as for x^0, with x≠0, or with the argument of the limit x^x, with x —> 0+,
I can't help consider, as a dummy, x^0=x^(a-a),
with 0 = a-a for any a,
then x^(a-a) = x^a/x^a=(x/x)^a = 1^a... =1.

But stop! x is =0
—> with x/x, we have "0/0"...

But of course I am no mathematician.

A between (interesting, but perhaps not satisfactory) solution of the HP50G is indeef
0.^0. —> 1. (or 0.^0 —>1. or 0^0. —> 1., with the latter result not so clear for me),
with the dot that could be understood as "an approaching value",
and 0^0 in exact mode with the HP50G that results in '?'.